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[-eViL-]

limit  ((1+n)^(1/n)) = e
n->0

or

limit  ((1+(1/n))^n) = e
n->infinity

those are just fyi in you need them....
here is what you are trying to prove:

limit M((1+(k/n))^(n*t)) = C(e^(k*t))
n->infinity

it is basically the PeRT formula is equal to the compounding continously formula where C and M are both constants, t is time, and k is just some number (varies).

[Paradox666]

:roll:

[-Icer-]

it is basically the PeRT formula is equal to the compounding continously formula where C and M are both constants, t is time, and k is just some number (varies).

[-eViL-]

the problem is solving icer, solve the damn thing, its impossible because it requires dividing an equation by the (n*t) root which can get very frickin nasty very quickly and i need a better way to solve it.

if you want it a little better to read, go here:
http://www.geocities.com/evilssite/Calculus.html

[-Icer-]

its impossible because it requires dividing an equation by the (n*t) root which can get very frickin nasty very quickly and i need a better way to solve it.

I'm guessing it's not really impossible?

btw I know nothing of calculus =\

[remote-control]

im in precal pre ap, i remember doing the " as N approaches infinity" stuff, but not that deep

[Darwin]

In Algebra II, we just came across this thing called "imaginary numbers."  IMAGINARY NUMBERS!  WTHFGD is that?  I smarted off to my teacher and took a quiz with an imaginary pencil and an imaginary peice of paper.

[-eViL-]

In Algebra II, we just came across this thing called "imaginary numbers."  IMAGINARY NUMBERS!  WTHFGD is that?  I smarted off to my teacher and took a quiz with an imaginary pencil and an imaginary peice of paper.

whats wrong with imaginary numbers?

i is the square root of -1
i^2 is -1
i^3 is the negative square root of -1
i^4 is 4
and then the pattern repeats forever in multiplies of 4...

i^64 = i^(4*16) = i^4 = 1... they come in handy when reducing large exponents of i

[Darwin]

See, I got this ipod... see... and when I get in that class, the headphones go on.  He doesnt care.

[Newbie]

Do you actually enjoy math Evil?  

[-eViL-]

i live in math .

and by the way, the problem has been solved.

1. C0(e^kt) = M0 * (lim as n->inf of ((1+(k/n))^(nt)))

2. C0(e^kt) = M0 * 1

3. e^kt = M0/C0

4. ln e^kt = ln(M0/C0)

5. kt = ln(M0/C0)

6. C0(e^ln(M0/C0)) = M0 (from step 2, just plug in info)

7. C0 * (M0/C0) = M0

8. M0 = M0

problem solved.

[Newbie]

I feel stupid. 0_0

[Paradox666]

:?:

[remote-control]

imaginary numbers are easy... i love calculus, and trig is my fav subject in calculus.. sooooo much more interesting than alg 2 i feel.. cause it actually has meaning, and use..

[Nitelthrome]

Omg, what has the world gone to? POSTING MATH EQUATIONS ON A GAME FORUM??! Get that evil stuff outta here, this isn't math class!

I'll go get the de-contamination spray.