Post by: -eViL- on January 11, 2004 04:24 pm CST
n->0
or
limit ((1+(1/n))^n) = e
n->infinity
those are just fyi in you need them....
here is what you are trying to prove:
limit M((1+(k/n))^(n*t)) = C(e^(k*t))
n->infinity
it is basically the PeRT formula is equal to the compounding continously formula where C and M are both constants, t is time, and k is just some number (varies).
Post by: Paradox666 on January 11, 2004 04:26 pm CST
Post by: -Icer- on January 11, 2004 04:37 pm CST
Quote from: "-eViL-"
it is basically the PeRT formula is equal to the compounding continously formula where C and M are both constants, t is time, and k is just some number (varies).
Post by: -eViL- on January 11, 2004 04:40 pm CST
if you want it a little better to read, go here:
http://www.geocities.com/evilssite/Calculus.html (http://www.geocities.com/evilssite/Calculus.html)
Post by: -Icer- on January 11, 2004 04:48 pm CST
Quote from: "-eViL-"
its impossible because it requires dividing an equation by the (n*t) root which can get very frickin nasty very quickly and i need a better way to solve it.
I'm guessing it's not really impossible?
btw I know nothing of calculus =\
Post by: remote-control on January 11, 2004 04:54 pm CST
Post by: Darwin on January 11, 2004 05:21 pm CST
Post by: -eViL- on January 11, 2004 05:26 pm CST
Quote from: "Darwin"
In Algebra II, we just came across this thing called "imaginary numbers." IMAGINARY NUMBERS! WTHFGD is that? I smarted off to my teacher and took a quiz with an imaginary pencil and an imaginary peice of paper.
whats wrong with imaginary numbers?
i is the square root of -1
i^2 is -1
i^3 is the negative square root of -1
i^4 is 4
and then the pattern repeats forever in multiplies of 4...
i^64 = i^(4*16) = i^4 = 1... they come in handy when reducing large exponents of i
Post by: Darwin on January 11, 2004 05:27 pm CST
Post by: Newbie on January 11, 2004 05:46 pm CST
Post by: -eViL- on January 11, 2004 05:56 pm CST
.and by the way, the problem has been solved.
1. C0(e^kt) = M0 * (lim as n->inf of ((1+(k/n))^(nt)))
2. C0(e^kt) = M0 * 1
3. e^kt = M0/C0
4. ln e^kt = ln(M0/C0)
5. kt = ln(M0/C0)
6. C0(e^ln(M0/C0)) = M0 (from step 2, just plug in info)
7. C0 * (M0/C0) = M0
8. M0 = M0
problem solved.
Post by: Newbie on January 11, 2004 05:57 pm CST
Post by: Paradox666 on January 11, 2004 06:07 pm CST
Post by: remote-control on January 11, 2004 06:56 pm CST
Post by: Nitelthrome on January 11, 2004 08:25 pm CST
I'll go get the de-contamination spray.
Post by: remote-control on January 11, 2004 09:54 pm CST
Post by: -eViL- on January 11, 2004 09:59 pm CST
Post by: remote-control on January 11, 2004 10:01 pm CST
Quote
nitel, some people on these forums do care about math because they like it and with that said, you can either shut the fragglewert up or you can just get the fragglewert lost because i don't believe we need your shizzle comments spamming up the forum with useless stuff like "i hate that" or "get rid of it" because we need to get rid of your opinionated ass.
pwned
Post by: DeadBreed on January 11, 2004 10:04 pm CST
Quote from: "remote-control"
Quotenitel, some people on these forums do care about math because they like it and with that said, you can either shut the fragglewert up or you can just get the fragglewert lost because i don't believe we need your shizzle comments spamming up the forum with useless stuff like "i hate that" or "get rid of it" because we need to get rid of your opinionated ass.
pwned
Post by: KoRo on January 11, 2004 11:04 pm CST
Post by: remote-control on January 11, 2004 11:58 pm CST
Post by: DeadBreed on January 12, 2004 12:01 am CST
Post by: remote-control on January 12, 2004 12:12 am CST
Post by: Hack-N-Slash on January 12, 2004 06:21 am CST
Oh yeah, I do great in math, but this thing called homework (meant to keep lazy, yet intelligent students consider suicide) kept me for showing how good I was... I ace tests, I don't do homework
I look forward to college calc
Post by: -eViL- on January 12, 2004 02:09 pm CST
derivitives can be cool... depending on what you have to take the derivitive of, then it can be a pain in the ass... find the derivitive of y with respect to x is what it means y = (ln(tan(x)sec(x)))^3
so overall, math isn't bad, but calculus you really have to understand and like to do good at...
and by the way, the answer to the question in paragraph 2 is:
y' = (3(ln(tan(x)sec(x)))^2) * (1/(tan(x)sec(x))) * (sec^2(x)sec(x)tan(x))
simplify:
y' = (3(ln(tan(x)sec(x)))^2) * (sec^2(x))
Post by: Nitelthrome on January 12, 2004 02:24 pm CST
Maybe you're right, eVil, I should leave if I don't like it and you all do. The only thing that would hold me back is the satisfaction you would feel. But then again, the only reason I stop by these forums is for help and the continuous story. But now that's basically dead. All the fun has been sucked out and replaced with math prolems. I suppose I'm wasting time here. Cya all later, then! I'll be on the TRPG forums.
humpfest pwns
Post by: -eViL- on January 12, 2004 02:30 pm CST
Post by: Nitelthrome on January 12, 2004 02:35 pm CST
Post by: -eViL- on January 12, 2004 02:37 pm CST
Post by: Nitelthrome on January 12, 2004 02:39 pm CST
Post by: Newbie on January 12, 2004 02:50 pm CST
Can't wait to take Precal next year.
Post by: Nitelthrome on January 12, 2004 03:10 pm CST
Post by: Quaduce on January 12, 2004 03:17 pm CST
Post by: Nitelthrome on January 12, 2004 03:28 pm CST
Post by: Newbie on January 12, 2004 04:48 pm CST
Quote from: "Nitelthrome"
Sorry, that's not acceptable. If you do not like math, you do not belong here. We are not open to discuss diversity.
Quote from: "Newbie"
I don't like advanced math at all (I have a C in ALG 2 right now).. but hey, whatever floats your boat.
Can't wait to take Precal next year. :roll:
Post by: Darwin on January 12, 2004 05:30 pm CST
God I wish I coulda just quit math after long division...
Post by: Silvanoshei on January 12, 2004 05:50 pm CST
No one's forcing you to enter this thread just because you haven't spammed it yet. If you don't like it, then get the hell out.
Post by: Nitelthrome on January 12, 2004 06:13 pm CST
But just like Quad said, people who do math in their spare time seriously do have no life...and Silv, don't reply back with one of your posts where you show of your great skills in using bold and italics.
Post by: Silvanoshei on January 12, 2004 06:21 pm CST
Quote from: "Nitelthrome"
people who do math in their spare time seriously do have no life
How can you judge what he does with his life by hearing about his spare time? Yes, that's right. I utilized the forum by typing seven extra characters. I guess I have no life, do I, then? What do you do in your spare time, O Essence of Life?
Post by: -eViL- on January 12, 2004 07:14 pm CST
Quote from: "Quaduce"
sorry but if you discuss math problems in your spare time then you really have no life at all.
Quote from: "Nitelthrome"
Alright, cya then.
But just like Quad said, people who do math in their spare time seriously do have no life...and Silv, don't reply back with one of your posts where you show of your great skills in using bold and italics.
who ever said it was my spare time, people do have homework to do in this world and when you come across something interesting, its always nice to know how and why it works.
Post by: Nitelthrome on January 12, 2004 07:19 pm CST
And Silv, look at the forking web address you're at right now. Then ask me what I do in my spare time.
Post by: remote-control on January 12, 2004 09:29 pm CST